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pav-90 [236]
3 years ago
9

How many milliliters of 0.50 M KOH are needed

Chemistry
1 answer:
spayn [35]3 years ago
3 0

Answer:

Option D. 30 mL.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above,

The mole ratio of the acid, nA = 1

The mole ratio of the base, nB = 1

Step 2:

Data obtained from the question. This include the following:

Volume of base, KOH (Vb) =.?

Molarity of base, KOH (Mb) = 0.5M

Volume of acid, HNO3 (Va) = 10mL

Molarity of acid, HNO3 (Ma) = 1.5M

Step 3:

Determination of the volume of the base, KOH needed for the reaction. This can be obtained as follow:

MaVa / MbVb = nA/nB

1.5 x 10 / 0.5 x Vb = 1

Cross multiply

0.5 x Vb = 1.5 x 10

Divide both side by 0.5

Vb = (1.5 x 10) /0.5

Vb = 30mL

Therefore, the volume of the base, KOH needed for the reaction is 30mL.

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0.4

Explanation:

Given data:

Number of moles of SrCl₂ consumed = ?

Mass of ZnCl₂ produced = 54 g

Solution:

Chemical equation:

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Number of moles of ZnCl₂:

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Number of moles = 0.4 mol

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                          ZnCl₂              :             SrCl₂

                              1                  :                1

                           0.4                 :              0.4

Thus when 54 g of  ZnCl₂ produced 0.4 moles of SrCl₂ react.

6 0
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Which of the following best describes a Lewis base?
PolarNik [594]
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Nuetrik [128]
Missing in your question:
Picture (1)
when its an open- tube manometer and the h = 52 cm. 
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Picture (2)
The pressure of the gas is the pressure experts by the column of mercury and when we have the Height (Hg)= 67mm 
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Picture (3) 
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