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lesya692 [45]
3 years ago
12

Consider the steps in coal gasification: C(coal) + H2O(g) → CO(g) + H2(g) ΔH°rxn = 129.7 kJ CO(g) + H2O(g) → CO2(g) + H2(g) ΔH°r

xn = -41 kJ CO(g) + 3H2(g) → CH4(g) + H2O(g) ΔH°rxn = -206 kJ Calculate the heat of reaction, ΔH°rxn, for overall reaction for the production of methane, CH4.
Chemistry
1 answer:
Volgvan3 years ago
4 0

Answer:

The answer to your question is  ΔHrxn = 0 kJ

Explanation:

  Process

1.- Multiply Equation 1 by 2

           2C(coal) + 2H₂O   ⇒   2CO (g) + 2H₂      ΔH rxn = 259.4 kJ

2.- Sum equation 2

           CO(g)     +  H₂O    ⇒    CO₂ (g)  + H₂ (g)   ΔHrxn = -41 kJ

Result

2C + 3H₂O + CO  ⇒  2CO + 3H₂ + CO₂               ΔHrxn =  218.4 kJ

Simplification

        2C + 3H₂O  ⇒   CO + 3H₂  + CO₂    

3.- Sum equation 3

       CO(g) + 3H₂ (g)  ⇒  CH₄ (g)  +  H₂O  (g)       ΔHrxn = -218.4 kJ

Result

  2C + 3H₂O + 3H₂ + CO  ⇒   CO + 3H₂ + CO₂ + CH₄ + H₂O  

Simplification

                        2C + 2H₂O  ⇒   CO₂ + CH₄         ΔHrxn = 0 kJ

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