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Svetradugi [14.3K]
3 years ago
10

Add 8x to 2x and then subtract 5 from the sum. If x is a

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:10

Step-by-step explanation:

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How to do this question plz answer my question ​
Degger [83]

Answer:

$121.82

Step-by-step explanation:

Okay, this is kind of complex, so let's go step by step.

First, we want to find the area of the rectangular lawn - we can do this by multiplying the length and width. The length is 100 and the width is 45 so 45\cdot100=4500 m² is the area of the rectangle.

However, there are 3 ponds in which the grass seeds will not be going - so we need to find the area of all 3 of these circles and subtract it from 4500 (our rectangle area).

The area of a circle is represented by the formula \pi r^2

The diameters are given here, which is double the radius, so to find the radius of each circle let's divide the diameters by 2.

First circle's radius: 20\div2=10

Second circle's radius: 10\div2=5

Third circle's radius: 5\div2=2.5

Now let's find the area of each circle.

<em>First Circle</em>: \pi \cdot10^2 = \pi\cdot100=3.14\cdot100=314

<em>Second Circle</em>: \pi\cdot5^2 = \pi \cdot25 = 3.14\cdot25=78.5

<em>Third Circle:</em> \pi \cdot 2.5^2 = \pi \cdot6.25 = 3.14\cdot6.25=19.625

Adding all of these values gets us 412.125.

Now we can subtract from this from 4500 to get us 4087.875

If the grass seeds that cost £1.49 cover 50m² each, then we need 4087.875\div50=81.7575 bags.

Each bag costs £1.49, so the total cost is 81.7575\cdot1.49\approx121.82

Hope this helped!!

5 0
3 years ago
Assume y≠60 which expression is equivalent to (7sqrtx2)/(5sqrty3)
Drupady [299]

Answer:

The equivalent will be:

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)

Therefore, option 'a' is true.

Step-by-step explanation:

Given the expression

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}

Let us solve the expression step by step to get the equivalent

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}

as

\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}      ∵ \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}

\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

=x^{2\cdot \frac{1}{7}}

=x^{\frac{2}{7}}

also

\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}         ∵  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}

\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

=y^{3\cdot \frac{1}{5}}

=y^{\frac{3}{5}}

so the expression becomes

\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)            ∵ \:\frac{1}{y^{\frac{3}{5}}}=y^{-\frac{3}{5}}

Thus, the equivalent will be:

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)

Therefore, option 'a' is true.

5 0
3 years ago
Please help I don’t understand this at all
Natalka [10]

Answer: 33.5

Step-by-step explanation:

8 0
3 years ago
Z/-2.5-011.5=-1.34 what is z
ololo11 [35]

Answer:

z=-25.4

Step-by-step explanation:

Add 11.5 to both sides of the equation, then simplify. Multiply all terms by the same value to eliminate fraction denominators

3 0
3 years ago
Who play pubg? Check out my account : sweetiepie67 ​
MArishka [77]

Answer:

\blue{\underline{\underline{\sf{Answer :-}}}}

★ in india pubg is banned

6 0
3 years ago
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