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Salsk061 [2.6K]
3 years ago
5

Which expression is equivalent to 15p^-4q^-6/-20p^-12q^-3 in simplified from? assume p=/ 0,q=/0

Mathematics
2 answers:
iogann1982 [59]3 years ago
5 0

Answer:The correct answer for this problem is 3p^8/-4q^3

Step-by-step explanation:

enyata [817]3 years ago
3 0
(15p⁺⁴.q⁻⁶) /(-20p⁻¹².q⁻³). 

Remember that  a⁻ⁿ = 1/aⁿ  and 1/a⁻ⁿ = aⁿ


(-15/4).(p⁻⁴.q⁻⁶)(p⁺¹².q⁺³). 

(-15/20).(p⁻⁴.p¹².q⁻⁶.q³)

Remember aⁿ.aˣ = aⁿ⁺ˣ

(-15/20).(p⁸.q⁻³)

-3/5(p⁸.q⁻³)


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Can the degree of a monomial ever be a negative? please explain why or why not.
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Greetings!

Yes, the degree on a monomial can be negative:

Example:
9x^{-2}

This is equal to:
1/9x^{2}

Hope this helps.
-Benjamin
3 0
3 years ago
The sum of three times a number, and 3, is equal to two times the number.
ale4655 [162]

3x + 3 = 2x

three times a number = 3x ,and 3 = 3x + 3, is equal to two times the number =

3x + 3 = 2x

6 0
3 years ago
What will be the result of substituting 2 for x in both expressions below? One-half x + 4 x + 6 minus one-half x minus 2 Both ex
tiny-mole [99]

Replace x with 2 and solve each equation:

1/2(2) + 4 = 1 + 4 = 5

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The answer is:

both expressions equal 5 when substituting 2 for x because the expressions are equivalent.

7 0
2 years ago
Find the sum of each set of numbers, as well as the size n of each set of numbers (n = number of numbers in the set). Use these
guapka [62]

We have to add numbers without a calculator.

1) 25, 35, 19, 31

We can group them by the last digit, so they are easy to add:

25 + 35 = 20 + 30 + 5 +5 = 50 + 10 = 60

19 + 31 = 10 + 30 + 9 +1 = 40 + 10 = 50

Then, 60 + 50 = 110

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Sum = 110

2) 101, 73, 49, 27, 24, 36

We can group them again by the last digit (adding 10, like the previous example).

We can substract the last digit from one number and add it to the other one. The result will be the same, but they will become easier to add.

101 + 49 = 100+50 = 150

73 + 27 = 70 + 30 = 100

24 + 36 = 20 + 40 = 60

150 + 100 + 60 = 250 + 60 = 310

numbers in the set n = 6

Sum = 310

3) 25, 25, 25, 30, 30, 30, 32, 32, 32

In this case we have 3 times the same numbers, so we can add the three different numbers and then multiply the total by 3.

We can use the properties of the multiplication to simplify the product (we will use the distributive property)

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8 0
1 year ago
Cound someone please help me on this, I'm stuck. ​
Katyanochek1 [597]

Negative exponents work like this:

a^{-b}=\dfrac{1}{a^b}

So, in order to evaluate a negative exponent, you simply have to invert the base, and then raise to the positive equivalent of the exponent.

As an example, here are the first three exercises:

8^{-3}=\dfrac{1}{8^3}=\dfrac{1}{512}

(-4)^{-5}=\dfrac{1}{(-4)^5}=-\dfrac{1}{1024}

2k^{-4}=\dfrac{2}{k^4}

You can work out the rest applying this logic.

5 0
3 years ago
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