Answer:
See explanation
Explanation:
% optical purity = specific rotation of mixture/specific rotation of pure enantiomer * 100/1
specific rotation of mixture = 23°
specific rotation of pure enantiomer = 61°
Hence;
% optical purity = 23/61 * 100 = 38 %
More abundant enantiomer = 100% - 38 % = 62%
Hence the pure (S) carvone is (-) 62° is the more abundant enantiomer.
Enantiomeric excess = 62 - 50/50 * 100 = 24%
Hence
(R) - carvone = 38 %
(S) - carvone = 62%
An ionic compound is a compound between a metal and a non metal where the metal (normally from group 1 or 2) transferrs an electron to the non metal ( most commonly from group 6 or 7) . this is so that both atoms have a full outer shell of electrons. the metal gains a positive charge and the non metal a negative charge. they are held together by electrostatic forces of attraction. an example would be sodium chloride (salt) sodium is in group 1 and chlorine in group 7 so sodium transfers one electron :)
The answer is true. oxygen, the terminal electron acceptor, and water is formed as the product. pass through special proton channel proteins called ATP synthase. Arrange the following electron acceptors in the proper order in which they participate in electron transport. When oxygen accepts electrons, water is produced as a byproduct.
PV=nRT
P= ? atm
V= 2 L
T= 423 K
n= 2.3 moles
R= 0.08205
(P)(2)=(2.3)(0.08205)(423)
P= (79.826445)/(2)
P= 39.9132225 atm