Initial [ HCO2H] = moles * volume
=0.35 moles * 1 L = 0.35 M
by using ICE table:
HCO2H ↔ H+ + HCO2-
initial 0.35 M 0 0
change - X +X +X
Equ (0.35 - X) X X
∴ Ka = [H+][HCO2-] / [HCO2H]
by substitution:
1.8 x 10^-4 = X^2 / (0.35-X) by solving for X
∴ X = 0.0079 or 7.9 x 10^-3
∴ [H+] = X = 7.9 x 10^-3 M
Easy just convert it to feet the answer is <span>1113.51706 Feet
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1) Ca-37, with a half-life of 181.1(10) ms.
Answer:
An oxidising agent oxidises something else. Oxidation is loss of electrons (OIL RIG). That means that an oxidising agent takes electrons from that other substance.
Explanation: