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Advocard [28]
3 years ago
6

What is the formula of zinc sulphate?​

Chemistry
2 answers:
inessss [21]3 years ago
6 0

_____________________________

Question: What is the formula of zinc sulphate?

Answer: The formula of zinc sulphate is ZnSO4. It contains one atom of zinc one atom of sulphur and four atom of Oxygen. It is colourless compound. It is an acidic salt which is formed by the reaction of Zinc Hydroxide and Sulphuric acid. It turns blue litmus paper into red which proves that it is acidic in nature.

_____________________________

gtnhenbr [62]3 years ago
6 0

\bold{ANSWER}

ZINC SULPHATE = ZnSO4

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ΔH° of the reaction is -747.54kJ

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Based on gas law, it is possible to find the ΔH of a reaction using ΔH of half reactions.

Using the reactions:

<em>(1) </em>C(graphite) + 1/2O₂(g) → CO(g) ΔH° = -110.5 kJ

<em>(2) </em>CO(g) + 1/2O₂(g) → CO₂(g) ΔH° = -283.0 kJ

<em>(3) </em>H₂(g) + 1/2O₂(g) → H₂O(l) ΔH° = -285.8 kJ

<em>(4) </em>C(graphite) + 2H₂(g) → CH₄(g) ΔH° = -74.81 kJ

<em>(5) </em>CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH° = -890.3 kJ

The sum of 4×(4) + (5) gives:

4C(graphite) + 8H₂(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -74.81 kJ ×4 - 890.3 kJ = -1189.54kJ

Now, this reaction - 4×(1) gives:

4CO(g) + 8H₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -1189.54kJ - 4×-110.5 = <em>-747.54kJ</em>

<em></em>

Thus <em>ΔH° of the reaction is -747.54kJ</em>

3 0
3 years ago
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