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andrew-mc [135]
3 years ago
8

I don’t know if it’s true or false I need help

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

True

Step-by-step explanation:

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I can’t explain how many times I have tried to work out this problem. Im starting to think it’s impossible can someone help?
Anarel [89]

Answer:

13/3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Use a number line to find the quotient <br> 3/5 divided by 3/10<br> (———————————)
frutty [35]

Answer:

2 ( plot the answer on 2)

Step-by-step explanation:

We do the reciprocal of 3/10 because we are dividing fraction. Which would be 10/3. Change the sign to multiplication because we are dividing fractions. And multiply regularly. SO it would be 3/5 times 10/3 = 2

5 0
3 years ago
What is the domain of the function f(x) = x+1 / x2-6x+8
Ostrovityanka [42]

For this case we have that by definition, the domain of a function, is given for all the values for which the function is defined.

We have:

f (x) = \frac {x + 1} {x ^ 2-6x + 8}

The given function is not defined when the denominator is equal to zero. That is to say:

x ^ 2-6x + 8 = 0

To find the roots we factor, we look for two numbers that when multiplied give as a result "8" and when added as a result "-6". These numbers are:

-4-2 = -6\\-4 * -2 = 8

Thus, the factored polynomial is:

(x-4) (x-2) = 0

That is to say:

x_ {1} = 4\\x_ {2} = 2

Makes the denominator of the function 0.

Then the domain is given by:

All real numbers, except 2 and 4.

Answer:

x |x≠2,4

7 0
3 years ago
What number divided by 3 gives 12 as the result? A. -36 B. -4 С. 4 D. 36​
rodikova [14]
The answer is 36 all you do is divide the answer choices by 3 to get your answer
3 0
4 years ago
Someone please help on this problem ?
Wewaii [24]

Answer:

CR = 17 ; PR = 30

Step-by-step explanation:

From the problem hypothesis we know that CD⊥PR or CQ⊥PR(perpendicular) and ∡PCQ ≡∡RCQ (bisector)

so ∡PCQ≡∡RCQ

     [CQ]≡[CQ] (common side)

     CQ⊥PR

--------------------------------------------

⇒(cathetus - angle case of congruence)⇒ ΔPQC≡ΔRQC so [PQ]≡[QR] (=15) // PR = PQ+QR ⇒ PR=30

from this congruence ⇒ΔPRC = isosceles so PC=CR=17

Hint: in any triangle is bisector of an angle it is perpendicular on the opposite side then triangle is isosceles.

7 0
3 years ago
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