Answer:
i. sin(C) = ![\frac{\sqrt{3} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D)
ii. tan(C) = ![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
iii. sin(B) = ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Step-by-step explanation:
Given a right angled triangle ABC, with a right angle at A.
<ABC = ![30^{0}](https://tex.z-dn.net/?f=30%5E%7B0%7D)
<BCA = ![60^{0}](https://tex.z-dn.net/?f=60%5E%7B0%7D)
AC = 9 = 1
CB = 18 = 2
Applying Pythagoras theorem to ΔABC, we have;
AB = ![\sqrt{BC^{2} - AC^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7BBC%5E%7B2%7D%20-%20AC%5E%7B2%7D%20%7D)
= ![\sqrt{2^{2} - 1^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B2%5E%7B2%7D%20-%201%5E%7B2%7D%20%20%7D)
= ![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
Thus applying the trigonometric ratios, it would be observed that;
i. sin(C) = ![\frac{\sqrt{3} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D)
ii. tan(C) = ![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
iii. sin(B) = ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
The slope for the line would be a triangle
Answer:
Please put the answer horizontal how it is makes my head hurt
Step-by-step explanation:
Answer:
Step-by-step explanation:
1hr = $7.00
Therefore,
5 + 4 x 7
= $63
DV = Hours of work.
Represent even numbers as "2n" since each is a multiple of 2.
Represent odd numbers as "2n+1" since each is one more than an even.
-----------------
Your problem:
smaller # : 2n
larger #: 2n+2
-------------------
EQUATION:
2n+2 + 3(2n) = 234
8n = 232
n = 29
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smaller = 2*29 = 58
larger = 2n+2 = 60