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worty [1.4K]
3 years ago
6

A giant scoop, operated by a crane, is in the shape of a hemisphere of radius 24 inches. The scoop is filled with molten steel.

The steel is then poured into a cylindrical storage tank with diameter 32 inches. How high will the molten steel rise?
Mathematics
1 answer:
shtirl [24]3 years ago
6 0

Answer:

40 inches

Step-by-step explanation:

Volume, V of hemisphere = 2/3 π r^3

Radius, r = 24 inches ;

V = 2/3 π 24^3

V = 28952.917 in³

Volume of cylinder = π r^2 * h

h = height ; r = Radius = 32 /2 = 16 inches

Volume of hemisphere = volume of cylindrical tank

28952.917 = π (16)^2 * h

28952.917 = 804.24771h

h = 28952.917 / 804.24771

h = 35.9999

h = 40 inches

Molten stell rise is 40 inches

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Alexxandr [17]

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Solve both by elimination can someone help?<br> 2x-5y=-9 , 4x+5y=12<br><br> 3x-2y=12 , 7x-5y=17
lyudmila [28]

Answer:

x=1/2, y=2;    

Step-by-step explanation:

First pair:

2x-5y =-9

4x+5y=12

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Answer:

Option B

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Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

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f(x)=\frac{3}{4}x

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8 0
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Please help me!<br> Find the number x such that f(x) =1
STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

f(x) = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

1 = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

This has two equations. So, we can separate them into two separate cases. Namely:

1=-\frac{1}{2}x-1\text{ or } 1=x

Let's solve for x in each case.

Case I:

We have:

1=-\frac{1}{2}x-1

Add 1 to both sides:

2=-\frac{1}{2}x

Let's cancel out the fraction by multiplying both sides by -2. So:

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The right side cancels:

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Flip:

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So, x is -4.

Case II:

We have:

1=x

Flip:

x=1

This is the solution for our second case.

So, we have:

x_1=-4\text{ or } x_2=1

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

x_1=-4\text{ or } x_2=1

Out of our answer choices, we can pick D.

And we're done!

7 0
3 years ago
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