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VARVARA [1.3K]
3 years ago
10

Please help me explain as well. I will give brainliest.

Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

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The sum of three consecutive numbers is 42. What are the numbers?
Lorico [155]
 The three consecutive numbers.....12+14+16=42
4 0
3 years ago
Read 2 more answers
a sample of 412 adults showed that 293 of them are connected the the internet from home. Construct and interpret a 90% confidenc
Anna [14]

Answer:

CI = (0.674, 0.748)

Step-by-step explanation:

The confidence interval of a proportion is:

CI = p ± SE × CV,

where p is the proportion, SE is the standard error, and CV is the critical value (either a t-score or a z-score).

We already know the proportion:

p = 293/412

p = 0.711

But we need to find the standard error and the critical value.

The standard error is:

SE = √(p (1 − p) / n)

SE = √(0.711 × (1 − 0.711) / 412)

SE = 0.0223

To find the critical value, we must first find the alpha level and the degrees of freedom.

The alpha level for a 90% confidence interval is:

α = (1 − 0.90) / 2 = 0.05

The degrees of freedom is one less than the sample size:

df = 412 − 1 = 411

Since df > 30, we can approximate this with a normal distribution.

If we look up the alpha level in a z score table or with a calculator, we find the z-score is 1.645.  That's our critical value.  CV = 1.645.

Now we can find the confidence interval:

CI = 0.711 ± 0.0223 * 1.645

CI = 0.711 ± 0.0367

CI = (0.674, 0.748)

So we are 90% confident that the proportion of adults connected to the internet from home is between 0.674 and 0.748.

5 0
3 years ago
Select the three expressions that are equivalent to 14+14+14+14+14+14+14+1414+14+14+14+14+14+14+14.​
AVprozaik [17]

Answer:

This question is incomplete.

Step-by-step explanation:

Where are the list of equivalent values?

One list might be 98+1414+918 (because there are  7 14's either side of the 1414.)

4 0
4 years ago
Read 2 more answers
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
Need to evaluate 256 and fraction 1/4
postnew [5]

Answer:

256fraction=1/4

256÷4=64

64 answer this fraction

6 0
3 years ago
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