The size of the sample they should take to estimate p with a 2% margin of error and 90% confidence is n = 1691.
In statistics, the margin of error is just the degree of a significant error in the outcomes of random sample surveys.
The formula of margin error is, E = z√((p-vector)(1 - (p-vector)) ÷ n)
E = 2% = 0.02
Confidence level = 90%
Now, the proportion is not given so adopt nominal (p-vector) = 0.05
The critical value at CL of 90% is 1.645.
Thus, making n the subject,
n = z²(((p-vector) × (1 - (p-vector))) ÷ E²)
n = 1.645²((0.5 × 0.5) ÷ 0.02²)
n = 1691.266
n ≈ 1691
Read more about the margin of error at
brainly.com/question/16141482?referrer=searchResults
#SPJ4
If the place to the right of where you are rounding is 5 or higher, you have to round up. If it is 4 or lower, you have to round down. In the hundreds place, there is a 4. That's lower than 5 meaning that you round down/stay. So, the nearest thousands place is 3,000.
Translation:
R ( - 5, - 5 ) → R` ( - 4, 2 )
- 4 = - 5 + 1, 2 = - 5 + 7;
The translation rule:
( x , y ) → ( x + 1, y + 7 )
Coordinates of the point U are (- 5, 1 )
- 5 + 1 = - 4, 1 + 7 = 8
The image of U is :
U` ( - 4, 8 )
14 boxes per hour
60/5=12
12*3=36
60/6=10
10*5=50
50-36=14
Well if you subtract 437.5 from 500 you get 62.5 that is the difference between them but in fraction form it would be 5/8.
