Answer:
19
Step-by-step explanation:
9 - (-10) = ?
To do this, we need to use the additive inverse and the method of K(eep)F(lip)C(hange)
So, the problem becomes: 9 + 10 = ?
Do the math, and you get your answer of 19.
hello :
<span>(-101)+102+(-103)+104+...+(-199)+200
=( </span>(-101)+(-103) +....+ (-199) ) +( (102) + ( 104) +....+(200))
let : A = ( (-101)+(-103) +....+ (-199) )
B = ( (102) + ( 104) +....+(200))
note : the sum n term of arithemtic sequence
S= n/2(u1 + un)
un = u1 +(n-1) d u1 : the first term d : the common diference
in A : u1= -101 d = -2 n = 49...
in B : u1 =102 d=2 n= 49
A = 49/2(-101-199) =-7350
B=49/2(102+200)=4949
(-101)+102+(-103)+104+...+(-199)+200 = A+B =-2401
Answer:
815
Step-by-step explanation:
First you put the value of x from the table into the formula provided.
<em>y = -670 + 33(x) </em><= plug in the x value from the table
<em>y = -670 + 33(45)</em> <= multiply 33 * 45
<em>y = -670 + 1485</em> <= add the two terms (which you will subtract because one is positive and one is negative.
<em>y = 815</em>
Well if you look at the number 14.583 and look at the 8 bcuz thats the number before the hundredth you would see if 8 is greater or less than 4 if its greater the 5 goes up to 6 but if its less the 5 stays the same. So long story short the answer would be 14.6
Answer: Richard will owe $2024 after 1 year if he takes advantage of this option.
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 1588.57
r = 24.5% = 24.5/100 = 0.245
n = 12 because it was compounded 12 times in a year.
t = 1 year
Therefore,.
A = 1588.57(1+0.245/12)^1 × 12
A = 1588.57(1+0.245/12)^12
A = 1588.57(1+0.0204)^12
A = 1588.57(1.0204)^12
A = $2024.2
