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Inessa05 [86]
3 years ago
14

Consider a square and a regular hexagon (a six-sided figure with sides of equal length). One side of the square is 25 feet longe

r than a side of the hexagon, and the two figures have the same perimeter. What are the lengths of the sides of each figure?
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
Square side length=75
Hexagon side length=50
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Simon has a scale model of the Concorde airplane. The actual length of the Concorde is approximately 200 feet. If the ratio of t
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The answer is:  "40 cm " .
_________________________________________________________
<u>Note</u>:
_________________________________________________________

\frac{200 ft }{ (x) cm} = \frac{5}{1}  ;

Solve for "x" (in "cm" ) ; 


→  5x = 200 * 1 ; 

→  5x = 200 ; 

Divide each side of the equation by "5" ; 
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→  5x / 5 = 200 / 5 ; 

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6 0
3 years ago
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tankabanditka [31]

Answer: a) P = 0.5, b) P = 0.07

Step-by-step explanation:

Hi!

Lets call X₁ the time at which you arrive, and X₂ the time at which Bob arrives. Both are random variables with uniform density in the interval [0, 60] (in minutes). Their joint distribuition is uniform over the square in the image, with value P = 1/(60*60) = 1/3600.

a) For you to get more cake than Bob, you should arrive earlier. This event is A = { X₁ < X₂ }, the shaded triangle in the figure.The area of this event (set) is half the total area of the square, so P(A) = 0.5.

It makes sense, beacuse its equally probable for you or Bob to arrive earlier, as both have uniform density over the time interval.

b) In this case you arrive later than Bob, but less than 5 minutes later. So the event is B = { X₂ < X₁ < (X₂ + 5) } . This is the gray shaded area in b) part of the image. Its area is the difference two triangles (half square - blue triangle), then the probability is:

P(B) = 0.5 - \frac{(0.5*55^2)}{3600} =0.07

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4 years ago
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Alekssandra [29.7K]
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3 years ago
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These solutions can be called “roots”, “zeroes”, and “x-intercepts”.
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