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Inessa05 [86]
3 years ago
14

Consider a square and a regular hexagon (a six-sided figure with sides of equal length). One side of the square is 25 feet longe

r than a side of the hexagon, and the two figures have the same perimeter. What are the lengths of the sides of each figure?
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
Square side length=75
Hexagon side length=50
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Find the volume and surface area of the composite figure. Give your answer in terms of pi
ExtremeBDS [4]

Given:

A diagram of a composite figure.

Radius of cone and hemisphere is 8 cm.

Height of the cone is 15 cm.

To find:

The volume and the surface area of the composite figure.

Solution:

Volume of a cone is:

V_1=\dfrac{1}{3}\pi r^2h

Where, r is the radius and h is the height of the cone.

Putting r=8,h=15 in the above formula, we get

V_1=\dfrac{1}{3}\pi (8)^2(15)

V_1=\pi (64)(5)

V_1=320\pi

Volume of the hemisphere is:

V_2=\dfrac{2}{3}\pi r^3

Where, r is the radius.

Putting r=8, we get

V_2=\dfrac{2}{3}\pi (8)^3

V_2=\dfrac{1024}{3}\pi

V_2\approx 341.3\pi

Now, the volume of the composite figure is:

V=V_1+V_2

V=320\pi +341.3\pi

V=661.3\pi

The volume of the composite figure is 661.3π cm³.

The curved surface area of a cone is:

A_1=\pi r\sqrt{h^2+r^2}

Where, r is the radius and h is the height of the cone.

Putting r=8,h=15 in the above formula, we get

A_1=\pi (8)\sqrt{(15)^2+(8)^2}

A_1=\pi (8)\sqrt{289}

A_1=\pi (8)(17)

A_1=136 \pi

The curved surface area of the hemisphere is:

A_2=2\pi r^2

Where, r is the radius.

Putting r=8, we get

A_2=2\pi (8)^2

A_2=2\pi (64)

A_2=128\pi

Total surface area of the composite figure is:

A=A_1+A_2

A=136\pi +128\pi

A=264\pi

The total surface area of the composite figure is 264π cm².

Therefore, the correct option is A.

8 0
3 years ago
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