The distance between two points knowing theirs coordinates:
AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(5,-4) & B(-3,-1) Given
A(x₁,y₁) & B(x₂,y₂)
AB =√[(-3-5))²+(-1-(-4)²] =√(73) = 8.381 ≈ 5.44 units
Let gradient of original line = m = 1/6
Gradient of line perpendicular to this = -1/m = -6
(Gradient = slope)
Answer:
61 years old
Step-by-step explanation:
26 plus 3 is 29 and 29 times 3 is 87 and 87 minus 29 is 61
Answer:
x= 37.5°
Step-by-step explanation:
∠CBD
= 180° -75° (adj. ∠s on a str. line)
= 105°
∠BCD= ∠BDC (base ∠s of isos. △BCD)
∠BCD= x
∠BCD +∠BDC +∠CBD= 180° (∠ sum of △BCD)
x +x +105°= 180°
2x= 180° -105°
2x= 75°
x= 37.5°
<u>Alternative</u><u> </u><u>working</u><u>:</u>
∠BDA= (180° -75°) ÷2 (base ∠s of isos. △ABD)
∠BDA= 52.5°
∠BDA +∠BDC= 90°
52.5° +x= 90°
x= 90° -52.5°
x= 37.5°