Answer: mean=87, median=87.5 and range=18
Step-by-step explanation:
Mean:
First add all the numbers
78+95+77+92+87+79+94+86+88+94 = 870
Then you divide the answer by counting the numbers
870÷10
=87
Median:
First arrange the numbers in ascending order (from smallest to largest)
77, 78, 79, 86, 87, 88, 92, 94, 94, 95
pick the two middle numbers which is 87 and 88
then you do 
= 175÷2
= 87.5
range = Largest number - smallest number
= 95-77
= 18
(2, -1), (6,- 4), and (6, -1). Hope this helps man!
Answer:
=38+x
Step-by-step explanation:
18-2+2x-24÷(x+2) =
16+2x-24-24÷(x+2)
24+16+2x
40+x+2
38+x
Answer:
66 ≤ f ≤100
Explanation
Mean= ( Σ x ) / n
Mean= sum of scores/ number of subject she took
Now, she already too 3 subject which sum is 85+83+86=254
Now we need to know range of score for her to have (grade) a mark between 80 and 89
Now let take the lower limit mean=80
The lowest score she can get is
Mean = ( Σx) / n
80=(85+83+86+f)/4
80×4= 254+f
Therefore, f= 320-254=66
Therefore the minimum score she can have to have a B is 66.
Then, let take the upper limit mean 89. i.e the maximum she can have so that she don't have an A grade.
Mean = ( Σx) / n
89=( 83+85+86+f)/4
89×4= 254+f
f= 356-254
f=102.
Therefore this shows that she cannot have an A grade in the exam. The maximum score for the exam is 100.
There the range of score is 66 ≤ f ≤100 to have a B grade
66 ≤ f ≤100 answer
Since she cannot score 102 in the examination.
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