Since the tool box has the dimensions of 10 in by 4 in by 7 in. The volume will be:
= 10 × 4 × 7
= 280in³
When the dimensions are doubled, the new dimensions will be:
10 in = 10in × 2 = 20in
4in = 4in × 2 = 8 in
7in = 7in × 2 = 14in
The volume will now be:
= 20 × 8 × 14
= 2240in³
He is wrong, the volume isn't the double of the former tool box. The double of the former tool box will give (280in³ × 2) = 560in³. This is different from the new volume.
