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Effectus [21]
3 years ago
8

A tool box has the dimensions of 10 in by 4 in by 7 in. If Magnus plans to double all three dimensions to build a larger tool bo

x, he believes he would double the volume of the tool box. Is he correct?
Mathematics
1 answer:
arsen [322]3 years ago
6 0

Answer: No. He's wrong.

Step-by-step explanation:

Since the tool box has the dimensions of 10 in by 4 in by 7 in. The volume will be:

= 10 × 4 × 7

= 280in³

When the dimensions are doubled, the new dimensions will be:

10 in = 10in × 2 = 20in

4in = 4in × 2 = 8 in

7in = 7in × 2 = 14in

The volume will now be:

= 20 × 8 × 14

= 2240in³

He is wrong, the volume isn't the double of the former tool box. The double of the former tool box will give (280in³ × 2) = 560in³. This is different from the new volume.

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Answer:

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Step-by-step explanation:

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3 years ago
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3 years ago
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An urn contains 1 liter of water while a second urn nearby is empty. after 1/2 of the water in the first urn is emptied into the
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We are given that there will be (1/2) a litre after the first pouring, so considering two successive pourings (n and (n+1)) with 1/2 litre in each before the nth pouring occurs:

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