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Effectus [21]
3 years ago
8

A tool box has the dimensions of 10 in by 4 in by 7 in. If Magnus plans to double all three dimensions to build a larger tool bo

x, he believes he would double the volume of the tool box. Is he correct?
Mathematics
1 answer:
arsen [322]3 years ago
6 0

Answer: No. He's wrong.

Step-by-step explanation:

Since the tool box has the dimensions of 10 in by 4 in by 7 in. The volume will be:

= 10 × 4 × 7

= 280in³

When the dimensions are doubled, the new dimensions will be:

10 in = 10in × 2 = 20in

4in = 4in × 2 = 8 in

7in = 7in × 2 = 14in

The volume will now be:

= 20 × 8 × 14

= 2240in³

He is wrong, the volume isn't the double of the former tool box. The double of the former tool box will give (280in³ × 2) = 560in³. This is different from the new volume.

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The area of a rectangle is<br> 3/8 in and the length is 5/8 What is the width?
liberstina [14]

Answer:

The width W is :

W=\frac{3}{5}

Step-by-step explanation:

<em>Let A be the area of the rectangle </em>

<em>Let L be the length of the rectangle</em>

<em>Let W be the width of the rectangle </em>

______

Formula:

A = L × W

__________

\begin{aligned}A &=L \times W \\\Rightarrow W &=\frac{A}{L} \\\Rightarrow W &=\frac{\frac{3}{8}}{\frac{5}{8}} \\&=\frac{3}{8} \times \frac{8}{5} \\&=\frac{3 \times 8}{8 \times 5} \\&=\frac{3}{5}\end{aligned}

6 0
3 years ago
Which of the following is equivalent to the expression 2x + 3x +4x (x-2)
Alex787 [66]

Answer:

a

Step-by-step explanation:

add and the take the parathesis out and there you have ur answer

4 0
3 years ago
Which of the following equations could be used to solve for the tenth term of the following sequence? 15,13,11,9,… A(10)=15+10(-
coldgirl [10]

Answer:

the first one

Step-by-step explanation:

3 0
2 years ago
PLZZZZ HELP What is the slope of a line that is perpendicular to a line whose equation is 3y=−4x+2 ?
earnstyle [38]

\bf 3y=-4x+2\implies y=\cfrac{-4x+2}{3} \\\\\\ y=\stackrel{\stackrel{slope}{\downarrow }}{-\cfrac{4}{3}}x+\cfrac{2}{3}\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}


so the slope of that line above is really -4/3, now


\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{4}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{4}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{4}\implies \blacktriangleright \cfrac{3}{4} \blacktriangleleft}}

6 0
3 years ago
Which equation represents a line that passes through (–9, –3) and has a slope of –6?
Fiesta28 [93]
Using slope-intercept form, y = mx + b where m = slope and b = y-intercept:

We know our slope is -6. This can be interpreted as -6/1, which rise-over-run-wise, means that when y changes by 6, x changes inversely by 1.
To find that y-intercept, though, we need to find the value of y when x = 0.
Use our point (-9, -3) to find this...
We want to add 9 to x so that it becomes 0.
According to our slope, this means subtracting 54 from y.
Our y-intercept is at (0, -57), with -57 being the value of b we put in our equation.

\boxed{y=-6x-57}

You could also just use point-slope form:
y - y¹ = m(x - x¹)
y - (-3) = -6(x - (-9))
y + 3 = -6(x + 9)
And convert to slope-intercept if you want:
y + 3 = -6x - 54
y = -6x - 57
3 0
3 years ago
Read 2 more answers
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