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3 years ago

HELP ME PLEASE!!,I WILL GIVE BRAINLIEST!!

Mathematics

2 answers:

Aliun [14]3 years ago

8 0

Answer:

Step-by-step explanation:

The answer is correct and cannot be simplified any further. Can I get that brainliest thay you promised me last time?

Hope this helps

Vera_Pavlovna [14]3 years ago

7 0

Answer:

The Answer is D!

Step-by-step explanation:

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The amount of snow fall falling in a certain mountain range is normally distributed with a mean of 74 inches, and a standard dev

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Given that the sample mean is μ=74 and sample standard deviation σₓ= $\frac{σ}{ \sqrt{n}} =\frac{12}{\sqrt{36}} =2$ .

Thge Z- score is $Z=\frac{76.8-74}{2} =1.4$ .

Now we use the Z-score to calculate the required probability.

Refer to standard normal distribution table.

The required probability is

$P(X>76.8) =P(Z>1.4)=1-P(Z$

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3 years ago

The highest possible z-score that is still in the bottom 95% of the systolic blood pressure distribution is z =−1.645 . Use this

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Answer:

(1) The value of X is, 151.13.

This score X, is the 95th percentile of systolic blood pressure scores among women. The percentile rank of this score is 95.

(2) The percentage of women have systolic blood pressure in the range 140 to 159 is 9.01%.

(3) The percentage of women having systolic blood pressure below 90 is 21.19%.

Step-by-step explanation:

The random variable X is defined as the systolic blood pressure of women.

The distribution of X is, N (110, 25²).

(1)

The value of z-score that is in the bottom 95% is, 1.645.

Compute the value of X as follows:

$z=\frac{X-\mu}{\sigma}\\1.645=\frac{X-110}{25}\\X=110+(1.645\times 25)\\X=151.125\\\approx151.13$

The value of X is, 151.13.

This score X, is the 95th percentile of systolic blood pressure scores among women. The percentile rank of this score is 95.

(2)

Compute the probability of X between 140 and 159 as follows:

$P(140$

The percentage of systolic blood pressure between 140 and 159 is,

0.0901 × 100 = 9.01%

Thus, the percentage of women have systolic blood pressure in the range 140 to 159 is 9.01%.

(3)

Compute the probability of X below 90 as follows:

$P(X$

The percentage of women having systolic blood pressure below 90 is,

0.2119 × 100 = 21.19%.

Thus, the percentage of women having systolic blood pressure below 90 is 21.19%.

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B does not represent a function

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4 years ago

a shopkeeper sold goods for rs 2400 and made a profit of 25% in the process. find his profit per cent if he had sold his goods f

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case 1,

Let the CP be ₹x,

SP = ₹2400

Profit = SP – CP

= 2400 – x

Profit % = {(2400–x)/ x} × 100%

According to the question,

{(2400–x)/ x} × 100 = 25

=> (2400–x)/ x= 25 /100

=> 100(2400–x) = 25x [ cross multiplication]

=> 240000 – 100x = 25x

=> 240000 = 25x + 100x

=> 240000 = 125x

=> 240000/125 = x

=> x = 1920

So, CP = ₹1920

case 2,

SP = ₹2040

Profit = SP – CP

= 2040 – 1920

= ₹120

profit % = 120/1920 × 100%

= 16%

<h3>Thus, his profit would be 16% if he had sold his goods for ₹2040.</h3>

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