Answer:
m<N = 76°
Step-by-step explanation:
Given:
∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).
m<J = 64° (given)
Required:
m<N
SOLUTION:
m<K = m<J (base angles of an isosceles ∆ are equal)
m<K = 64° (Substitution)
m<K + m<J + m<JLK = 180° (sum of ∆)
64° + 64° + m<JLK = 180° (substitution)
128° + m<JLK = 180°
subtract 128 from each side
m<JLK = 180° - 128°
m<JLK = 52°
In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.
Thus:
m<MLN = m<JKL (vertical angles are congruent)
m<MLN = 52°
m<M = m<MLN (base angles of isosceles ∆MNL)
m<M = 52° (substitution)
m<N + m<M° + m<MLN = 180° (Sum of ∆)
m<N + 52° + 52° = 180° (Substitution)
m<N + 104° = 180°
subtract 104 from each side
m<N = 180° - 104°
m<N = 76°
3⁹ is the same as doing:
3 * 3 * 3 * 3 * 3 * 3 * 3 * 3 * 3
What I would do it is narrow it down piece by piece.
3 * 3 * 3 = 27. Do that 3 times, now you are left with:
27 * 27 * 27
27 * 27 or 27² = 729.
That leaves you with:
729 * 27
You can multiply by hand or use a calculator to get your answer of 19683.
To check your answer, plug 3⁹ into a calculator. Your answer should match this.
Yes because 84+45 is 129 and 3(28+15) is 129
X=(b/2m)*y-e is the answer I believe.
