Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
Convert the decimal number to a fraction by placing the decimal number over a power of ten. Since there are 4 numbers to the right of the decimal point, place the decimal number over <span>104</span> (10000). Next, add the whole number to the left of the decimal.<span>4375\10000</span>Cancel the common factor of 625 in <span>437510000</span> since <span><span>4375\10000</span>=<span><span>7⋅625</span><span>16⋅625</span></span></span>.<span><span>74375</span><span>1610000</span></span>Reduce the expression <span>4375\10000</span> by removing a factor of 625 from the numerator and denominator.<span><span>7\16</span></span>
26+26=52 which is the side lengths.
116-52=64 which is the other side lengths together. So one side length 32. 32+32+26+26=116
Answer: 70
Step-by-step explanation:
10 x 7
Answer:
4x
Step-by-step explanation:
