To find the maximum height you need to find the vertex:(h,k)
Your equation is in vertex form a(x-h)+k and the vertex is (h,k) where k is the maximum height and the h is the distance it went to reach the maximum height.
k=6 so the kangaroo's maximum height is 6 feet.
To find how long is the kangaroo's jump, take a look at the graph. You will notice that the parabola ends at the distance the kangaroo jumped. You will also see that it is the one of the x-intercepts.
-.03(x-14)^2+6=0
-.03(x-14)^2+6-6=0-6
-.03(x-14)^2=-6
-.03/-.03(x-14)=-6/-.03
(x-14)^2=200
[(x-14)^2]^.5=200^.5
x-14=(200)^.5
x-14+14=(200)^.5+14
x≈28.14 feet
The kangaroo jumped a distance of 28.14 feet.
You will notice that the square root of a number gives you two solutions a positive and a negative one. The other solution is -.14, which we know distance is not negative so we do not use that solution. Also, I used the ^.5 instead of using the square root. It is the same.
3 = X/2 + 2
1 = X/2
2 = X
Jan had 2 pencils to start off with. She gave half (1 pencil) to Talia. Her brother gave her 2, which means she ends up with 3.
Answer:
feet
Step-by-step explanation:
We will use the Pythagorean Theorem to solve this. Which states that:
One Length^2 + Another Length^2 = Hypotenuse^2
We can take one length as 5 ft and another length as 9 ft and we call the hypotenuse "h", so we have:
Now, let us solve for "h":
The pond's hypotenuse is about 10.3 feet
No, the correct answer is 23.75. Try plugging it into a calculator.
