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vagabundo [1.1K]
2 years ago
6

what is the correct form of the partial fraction decomposition for: start fraction 35-27x over 4xsquared+28x endfraction

Mathematics
2 answers:
Elis [28]2 years ago
6 0

Answer: A

Step-by-step explanation:

cupoosta [38]2 years ago
4 0

Answer: The answer is A

Step-by-step explanation:

A/4x+B/x+7

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After a baseball is hit, the height h (in feet) of the ball above the ground t seconds after it is hit can be approximated by th
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Answer:

The ball will take 4.05 seconds to hit the ground.

Step-by-step explanation:

we have

h=-16t^{2}+64t+3

This is a quadratic equation (vertical parabola) open down

The vertex is a maximum

we know that

The ball hit the ground when h=0

Solve the quadratic equation

For h=0

-16t^{2}+64t+3=0

The formula to solve a quadratic equation of the form

at^{2} +bt+c=0 is equal to

t=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+64t+3=0  

so

a=-16\\b=64\\c=3

substitute in the formula  

t=\frac{-64(+/-)\sqrt{64^{2}-4(-16)(3)}} {2(-16)}

t=\frac{-64(+/-)\sqrt{4,288}} {-32}

t=\frac{64(-)\sqrt{4,288}} {32}=-0.05\ sec  ---> the time cannot be a negative number

t=\frac{64(+)\sqrt{4,288}} {32}=4.05\ sec

therefore

The ball will take 4.05 seconds to hit the ground.

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Find the function y = f(t) passing through the point (0, 18) with the given first derivative.
monitta

Answer:

\displaystyle y = \frac{t^2}{16} + 18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Coordinates (x, y)

<u>Calculus</u>

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]:                                                                   \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:                                                             \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (0, 18)

\displaystyle \frac{dy}{dt} = \frac{1}{8} t

<u>Step 2: Find General Solution</u>

<em>Use integration</em>

  1. [Derivative] Rewrite:                                                                                         \displaystyle dy = \frac{1}{8} t\ dt
  2. [Equality Property] Integrate both sides:                                                        \displaystyle \int dy = \int {\frac{1}{8} t} \, dt
  3. [Left Integral] Integrate [Integration Rule - Reverse Power Rule]:                 \displaystyle y = \int {\frac{1}{8} t} \, dt
  4. [Right Integral] Rewrite [Integration Property - Multiplied Constant]:           \displaystyle y = \frac{1}{8}\int {t} \, dt
  5. [Right Integral] Integrate [Integration Rule - Reverse Power Rule]:              \displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C
  6. Multiply:                                                                                                             \displaystyle y = \frac{t^2}{16} + C

<u>Step 3: Find Particular Solution</u>

  1. Substitute in point [Function]:                                                                         \displaystyle 18 = \frac{0^2}{16} + C
  2. Simplify:                                                                                                             \displaystyle 18 = 0 + C
  3. Add:                                                                                                                   \displaystyle 18 = C
  4. Rewrite:                                                                                                             \displaystyle C = 18
  5. Substitute in <em>C</em> [Function]:                                                                                \displaystyle y = \frac{t^2}{16} + 18

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

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Step-by-step explanation:

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