So you have y-y1=m(x-x1) and you are told that the slope has to be parallel to the line x-2y=6
1.) solve x-2y=6 for y
x-2y=6
Subtract x from both sides to get
-2y=6-x
Divide each side by -2 to get
y=-3-(x/2)
Now the slope for this equation is -1/2 and the line has to be parallel to this equation. Therefore the slope of the line that is parallel to this equation is going to be -1/2.
Now You have to use the point (2,-5) as your x1 and y1 and the slope that is parallel to the line x-2y=6, which is -1/2
y-(-5)=-1/2[x-(-2)]
Simplifying this you get
y+5=-1/2(x+2)
Above is how you write the equation in point slope form.
Now if it is asking you for slope-intercept form all you do is distribute -1/2 and subtract 5
y+5=-1/2(x+2)
y+5=-1x/2-1
Subtracting 5 from both sides gives you
y=-x/2 +4. Hope this helps. Let me know if you have questions
Answer:
To get your numerator you subtract the first two numbers, 63 - 49 = 14. That leaves you with 14 over 15 or . 93. Since the square root of 63 is higher than 7 but less than 8 your whole number is 7
Answer:
A = 450 cm²
Step-by-step explanation:
Since the right triangle is isosceles then the 2 logs are congruent , both 30 cm and at right angles to each other.
The area (A ) of the triangle is calculated as
A = bh ( b is the base and h the perpendicular height )
Here b = h = 30 , then
A = × 30 × 30 = × 900 = 450 cm²
Answer:
It's Impossible.
Matrix can only be raised to a power if it has same number of rows and columns
Step-by-step explanation:
Ms Smith has 28 sixth graders and 35 seventh graders
she wants to break them down into groups with each group having the same number of students from each grade
for this we have to find the highest common factor of 28 and 35 to see by which both 28 and 35 are divisible by
factors of 28 and 35 are as follows
28 - 1,2,4,7,14,28
35 - 1,5,7,35
the highest common factor both numbers is 7
therefore Ms Smith can break them down into 7 groups
each group will have
28 / 7 = 4 sixth graders
35 / 7 = 5 seventh graders
so each group will have 4 sixth graders and 5 seventh graders
so in each group there will be 4 + 5 = 9 students
she will break them down into 7 groups
each group has 9 students