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Answer: C.28 hope this helps!
Answer:
Step-by-step explanation:
Given:
Vertices of Hyperbola : (0 ± 6) or (0,6) and (0,-6)
and asymptotes at y= (±3/5)x 0r y= 3/5 x and y=-3/5 x
The vertices are of vertical hyperbola. The equation used will be:
The Center of hyperbola (h,k) =(0,0)
The Distance from vertices to center is a and a = 6 (given)
For equation we have value of h,k and a and need to find value of b
we know,
y= k ± a/b (x-h)
Values of h and k are zero
y= 0 ± a/b (x-0)
y= (± a/b ) x
We are given asymtotes at y= (± 3/5)x which is equal to y= (± a/b ) x
as a = 6 then b= 10 i.e The simplified form of 6/10 is 3/5 so value of b=10
Putting values of a,b,h and k in equation we get,
Answer:
The company should make 0 jumbo and 300 regular biscuits.
The maximum income is $42.
Step-by-step explanation:
Let's say J is the number of jumbo biscuits and R is the number of regular biscuits.
The oven can bake at most 300 biscuits. So:
J + R ≤ 300
Each jumbo biscuit uses 2 oz of flour, and each regular biscuit uses 1 oz of flour. There is 500 oz of flour available. Therefore:
2J + R ≤ 500
Income from jumbo biscuits is $0.12, and income from regular biscuits is $0.14. So the total income is:
I = 0.12J + 0.14R
Graph the two inequalities under the condition that J ≥ 0 and R ≥ 0:
desmos.com/calculator/aea00cmpwm
The region where the inequalities intersect has 4 corners:
(J, R) = (0, 0); (0, 300); (250, 0); (200, 100)
Find the income at each point:
(0, 0): I = 0
(0, 300): I = 42
(250, 0): I = 30
(200, 100): I = 38
The company makes maximum profit of $42 by baking 0 jumbo biscuits and 300 regular biscuits.
Answer:
No solution is possible from the information provided
Step-by-step explanation:
you didn't include the function.
