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Y_Kistochka [10]
3 years ago
7

If f(p) divided by x-p and x-q have the same remainder

Mathematics
1 answer:
oee [108]3 years ago
3 0
Hello,


x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)

Let's use Horner's division

.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3

The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3


Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0

And here, Mehek are there sufficients explanations?
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Which of the following is a factor of x2 − 21x + 110?
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(x - ?)(x - ?)
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borishaifa [10]
You can solve <span>9/x-4/y=8 for x or for y but NOT at the same time.

Solving for x:  </span><span>9/x-4/y=8       Mult all 3 terms by xy to eliminate the fractions.

9(xy)/x - 4xy/y = 8xy         =>       9y - 4x = 8xy, or 9y = 4x + 8xy = 4x(1+2y)

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                                                                                     9y
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Solve for y using a similar approach.

</span>
7 0
3 years ago
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