Answer: 207/4 or -51.75
Step-by-step explanation:
Number 2 for question 1 and number 4 for question 2
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
Step-by-step explanation:
If the tickets given to employees = 40
Then tickets given to listeners = 2 x no of employees tickets
= 2 x40 = 80
Total tickets = 40+ 80 = 120
[ - 4 , 4 ) ∪ ( 4 , ∞ )
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.
solve x - 4 = 0 ⇒ x = 4 ( is a vertical asymptote )
There is a zero when the numerator equals zero.
x + 4 = 0 ⇒ x = - 4 ( is a zero )
domain is [-4 , 4 ) ∪ ( 4 , ∞ )
