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dexar [7]
3 years ago
8

Question 4 (10 points)

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
3 0

use math photo It will be easy

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Which system of equations could be used to determine how many of each coin you have
kirza4 [7]
<h3>Answer: Choice A</h3>

0.10d + 0.05n = 2.25

d = 2n

================================================

Explanation:

n = number of nickels

d = number of dimes

we have twice as many dimes as nickels, so we could have something like 18 dimes and 9 nickels. Algebraically we would write d = 18 and n = 9. The equation that fits this is d = 2n. The answer is between A and B at this point.

We rule out choice B since the 0.05d is incorrect. It should be 0.10d to represent the total value of all the dimes.

Choice A is correct

d = number of dimes

0.10d = value of all the dimes in dollars

n = number of nickels

0.05n = value of all the nickels in dollars

0.10d + 0.05n = total value from both coins combined

2.25 =  total value from both coins combined

0.10d + 0.05n = 2.25

8 0
3 years ago
73 is what percent of 800
adoni [48]

Answer:

0.09125%

Step-by-step explanation:

Divide 73 by 800 and you will get 0.09125

3 0
3 years ago
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Hear is a poem
Mumz [18]

Answer:

wew so wha do you need help withhhhhhh

4 0
3 years ago
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What is 20 times 3/5 in simplest form?
eduard
20 x 3/5 would equal 12
7 0
3 years ago
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Can someone explain 3-10 for me I don't get it!!
kicyunya [14]
This can get confusing. Sorry if it doesn’t make a lot of sense. I will explain #3

1) You first have to look at the equation. It says 100 acres to 140 acres. From that information you should know that the number increases, so the percent will be over 100.
2)to set the equation up you do
X
__ =
100
Since every percent is out of 100.
3) Now you have to put the numbers in the equation. Since the original number is 15, so you would put it on the bottom and 18 on top.
X 18
__ = __
100 15
Then you times across
15x=1800
To find x (the percent) you divide both sides by 15
15x 1800
__ = __
15 15
X=120%
It would be increased
8 0
3 years ago
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