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Nata [24]
2 years ago
11

the scientists collection that as granite that weighs 74 26/36 lbs, marble that weighs 63 16/34 lbs, and quartz that weighs 81 9

/40 lbs. Approximatley each quantity to the nearest 1/4 how much more does the quartz weigh than the granite? 6 lbs 6 3/4 lbs 11 1/4 lbs 6 1/2 lbs
Mathematics
1 answer:
ipn [44]2 years ago
7 0

Answer:

<h2> 6 1/2 lbs</h2>

Step-by-step explanation:

Given the weight of granite to be  74 26/36 lbs,

Weight of quartz is 81 9/40 lbs.

To know how much more quartz weight than the granite, we will take the difference between the weight of quartz and granite as shown.

Weight of quartz  - Weight of granite

= 81 9/40 - 74 26/36

= 3,249/40 - 2690/36

= (29, 241 - 26,900)/360

= 2,341/360

= 6 181/360

≈ 6 1/2 lbs

quartz weighs approximately 6 1/2 lbs much more than granite

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5. (5 points) Write the first 5 terms of the sequence if a1 = 9 and an-1 +n
Ivanshal [37]

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9,4,-1,-6,-11

Step-by-step explanation:

When n = 1: a(1+1) =a(1) +1

                   a(2) = -9 +1

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When n = 2: a(2+1) =a(2) + 2

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6 0
2 years ago
Can you help please I am struggling thank you
Ludmilka [50]

Answer:

m<ADC = 107

Step-by-step explanation:

You need to know three things to solve this problem.

1) Opposite angles of an inscribed quadrilateral are supplementary.

2) The measure of an inscribed angle is half the measure of its subtended arc.

3) The sum of the measures of all the arcs of a circle is 360 deg.

From 1) we get:

m<A + m<C = 180

72 + m<C = 180

m<C = 108

From 2) we get:

m<C = (1/2)m(arc)BAD

108 = (1/2)[m(arc)AB + m(arc)AD]

216 = m(arc)AB + 122

m(arc)AB = 94

From 3) we get:

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94 + 120 + m(arc)CD + 122 = 360

m(arc)CD = 24

From 2) we get:

m<ADC = (1/2)m(arc)ABC

m<ADC = (1/2)[m(arc)AB + m(arc)BC]

m<ADC = (1/2)[94 + 120]

m<ADC = 107

3 0
2 years ago
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