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vaieri [72.5K]
3 years ago
9

Which of the following lists the types of copyright license from most restrictive to least restrictive?

Computers and Technology
2 answers:
scoundrel [369]3 years ago
3 0

Answer:

All Rights Reserved, Some Rights Reserved, Public Domain

Explanation:

Zolol [24]3 years ago
3 0

Answer:

that will be All Rights Reserved, Some Rights Reserved, Public Domain

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The means by which you interact with any program on a computer is called the ____. Answer
Elodia [21]
User interface is the answer
4 0
3 years ago
Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,
insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

3 0
3 years ago
Which of the following should NOT be done to keep people from slipping on floors? A) Have the proper absorbents in an easy-to-fi
RoseWind [281]

The following options helps keep people from slipping on floors

A) Have the proper absorbents in an easy-to-find place to quickly put on spills : So that accidental little spills can be cleaned right away.

C) Wear slip-resistant footwear : It is a precautionary step to follow, no matter where we go.

D) Mark a slippery area with an easy-to-use tent sign that says " Caution, Slippery floor" : This allows people to be aware of the wet area and cross it cautiously.

Leaving oil and fluids to air dry thoroughly, takes a long time and there are chances that people step over it and slip.

So, the answer is

(B) Anytime oil or fluids are spilled on the floor, leave them to thoroughly air dry.

8 0
3 years ago
Read 2 more answers
All it services and servers are equally critical. <br> a. True <br> b. False
g100num [7]

False

Not all IT services are equally critical. In an increasingly digital world whereby cyber threats are a big threat, it is vital to prioritize the critical assets in order to achieve digital resilience. This involves building tighter defenses in systems that are critical.

4 0
3 years ago
Your friend really likes talking about owls. Write a function owl_count that takes a block of text and counts how many words the
andriy [413]
Text = “ I really like owls. Did you know that an owls eyes are more than twice as big as the eyes of other birds of comparable weight? And that when an owl partially closes its eyes during the day, it is just blocking out light? Sometimes I wish I could be an owl.

word = ‘owl’
texts = text.lower()
owlist = list(texts.split())
count = text.count(word)
num = [owlist, count] #num has no meaning just random var
print(num)


Alter in anyway you want so that you can succeed. ✌
4 0
3 years ago
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