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2 years ago

Are composite numbers closed under multiplication

Mathematics

1 answer:

MrMuchimi2 years ago

3 0

Answer:

Remember that for a subset of a ring to be an ideal it must be closed under addition and under taking multiples by elements of the ring, and in this case the set of all composite integers is not closed under addition.

Step-by-step explanation:

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Eric and his two sister shared amount of money in ratio2:7 respectively. If Eric had 300.00 and the remaining amount shared equa

photoshop1234 [79]

Answer:

The equal amount is 525 .

Step-by-step explanation:

Given that,

Eric and his two sister shared amount of money in ratio2:7 respectively.

Amount with Eric = 300

It means,

2x = 300

x = 150

So,

7x = 7(150)

= 1050

As the remaining amount shared equally among the sister. So, the equal amount is 525 .

7 0

2 years ago

"More than 60% of the students scored below the mean on the last test." Can this statement be true? Why or why not?

Lelu [443]

The mean is the average of a set of numbers.

So if the remaining 40% of students score 100 points, and the 60% score like 50 points, then the mean would still be 70 points because of the 40% of students that scored super high.

So yes, it can be true.

8 0

3 years ago

Read 2 more answers

My grades is they good or bad on your opinion

Oxana [17]

Good!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

6 0

3 years ago

In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of

In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

A line segment joining the mid-points of two sides in a triangle is parallel to the third side and equal to half its length

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = $\frac{1}{2}$ MN

∵ JL = 11 units

∴ 11 = $\frac{1}{2}$ MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = $\frac{1}{2}$ MO

∵ KL = 13 units

∴ 13 = $\frac{1}{2}$ MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = $\frac{1}{2}$ ON

∵ ON =20 units

∴ JK = $\frac{1}{2}$ (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0

3 years ago

Gail can use her 12% employee discount once a week. Last Sunday, she bought a $45 sweater at 1/3 off and used her discount on th

NNADVOKAT [17]

Statement 1 : Gail bought a $45 sweater at 1/3 off.

Discount in Sweater Purchase:

$\frac{1}{3} \; of \; 45 = \frac{1}{3} \times 45 \; = \;\frac{45}{3} =\$15$

Statement 2: Gail can use her 12% employee discount once a week and used her discount on the suit priced at $140.

Discount in Suit Purchase:

$12\% \; of \; 140 =\frac{12}{100} \times 140 = 0.12 \times 140 = \$16.8$

Conclusion:

Discount in Suit Purchase ($16.8) is greater than Discount in Sweater Purchase ($15)

8 0

3 years ago

Read 2 more answers