Answer:
the answer is a.
Step-by-step explanation:
I plugged your data into a graphing calculator, and got a quad reg in the picture.
Answer:
71.63 kilowatts hours
Step-by-step explanation:
We are told in the question:
John's electricity bill costs $20.90 per month plus $1.23 per kilowatt hour.
We are to find, How many kilowatt hours can he use and keep his monthly cost no more than $109.
Step 1
$109 - $20.90
= $88.1
$88.1 is the amount left to spend on killowatts of electricity per hour after removing the normal monthly electricity bill in a month
Step 2
$1.23 = 1kilowatts per hour
$88.1 = y kilowatts per hour
Cross Multiply
= $1.23 × y kilowatts per hour = $88.1 × 1 kilowatts per hour
y kilowatts per hour = $88.1 × 1 kilowatts per hour/ $1.23
= 71.62601626kilowatts hour.
Approximately = 71.63 kilowatts hour
Therefore, John can use 71.63 kilowatts per hour and keep his monthly cost no more than $109
Choice I or option four is correct
Answer:
O The value of f(2) is smaller than the value of f(1).
Step-by-step explanation:
First, let's solve for both. When the problem says f(1) or f(2), this just means that the x value is equal to that. So:
f(1) = -5(1)^2 + 2(1) + 9 = 6
f(2) = -5(2)^2 + 2(2) + 9 = -7
Since f(1) = 6 and f(2) = -7, we know that f(1) is greater than f(2). Therefore, the value of f(2) is smaller than the value of f(1)
Answer:
b is 0
Step-by-step explanation:
yes, i am here :)