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SOVA2 [1]
3 years ago
10

Xander is planning on building a house. The blueprints show a house that is 3 inches wide and 2 inches tall. The blueprints use

a scale in which 14 inch represents 2 feet.
How wide and tall will the actual house be?

Drag and drop the height and width of the actual house into the boxes.
Mathematics
2 answers:
umka2103 [35]3 years ago
8 0

Answer:

16ft tall and 24ft wide

Step-by-step explanation:

creativ13 [48]3 years ago
3 0

Answer:

16ft 24ft

Step-by-step explanation:

i got the same qestion and its correct.

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LOOK AT PIC, ASAP, ROGHT ANSWER GETS BRAINLIEST !
k0ka [10]

Answer:

Step-by-step explanation:

The teacher has 7/8 pounds of clay given.

gives out 1/16 per station

7/8= 0.875 pound

7/8 / 1/16 pound= 14 maximum stations

14 stations divided by 2 classes = 7 in each room

5 0
3 years ago
I'LL GIVE BRAINLIEST!! PLEASE BE QUICK< I NED SLEPP! -v-'
allsm [11]
B) f(x)=-150x+1500

U started with 1500 and ur losing 150 every month

Thanks for the Brainliest!
6 0
3 years ago
Read 2 more answers
2. Two angles have a common vertex but no common side. How can you tell whether the angles are vertical angles?
Maksim231197 [3]

Explanation:

The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.

More formally, if V is the common vertex, and ...

  • R is a point on one of the rays forming Angle 1
  • S is a point on the ray that is the opposite of ray VR
  • T is a point on the other ray forming Angle 1
  • U is a point on the ray that is the opposite of ray VT

Then angle RVT and angle SVU are vertical angles.

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Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.

If the above conditions cannot be met, then the angles are not vertical angles.

7 0
4 years ago
HELP! last one of the day!
quester [9]
The bisector of the angle at A (call it AQ) divides the segment BC into segments BQ:QC having the ratio AB:AC. Use this fact to find x.

.. 9:15 = (2x -1):3x
.. 15(2x -1) = 9*3x . . . . . the product of the means equals the product of extremes
.. 30x -15 = 27x
.. 3x = 15
.. x = 5

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According to the value of x, the bisector AQ divides the triangle into two isosceles triangles: ABQ, ACQ.
7 0
3 years ago
(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi
Drupady [299]

Answer:

a. \dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. x(t) = 6\frac{2}{3} \cdot c \cdot t

c. c  = \dfrac{3}{8}  \ g/L

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx =  (5·c - 5·c/3)×dt = 20/3·c = 6\frac{2}{3} \cdot c \cdot dt

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. The amount of salt, x after t minutes is given by the relation

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

dx = 6\frac{2}{3} \cdot c \cdot dt

x(t) = \int\limits \, dx  = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt

x(t) = 6\frac{2}{3} \cdot c \cdot t

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10

6\frac{2}{3} \times c  =\dfrac{25 \ grams }{10}

c  =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} }  = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200}  \ g/L = \dfrac{3}{8}  \ g/L

c  = \dfrac{3}{8}  \ g/L

4 0
3 years ago
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