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3 years ago

Solve the system by substitution. 1. y = -6x – 7 y = -7x 2. -y=x 3x+5y=20

Mathematics

1 answer:

Drupady [299]3 years ago

8 0

Answer:

For no. 1:

One of the equations say that y=-7x

So plug in -7x to the other equation as y so you equation would be

-7x= -6x-7

And then, just solve for the variable:

*add -6x to both sides*:

-x= -7

*multiply both by negative one to get a positive variable*

FOR NUMBER 1, THE ANSWER IS:

x=7

Y=-7

For no. 2:

-y=x and your other equation is 3x+5y=20

Plug in x as -y:

-3y+5y=20

*simplify*

2y=20

*divide by 2 on each side to get 1 variable alone*

Y=10

FOR NUMBER 2, THE ANSWER IS:

x=-y

Y=10

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pishuonlain [190]

Answer: 2x + 5y = -5

Step-by-step explanation:

Two lines are said to be parallel if they have the same slope.

The equation of the line given :

2x + 5y = 10

To find the slope , we will write it in the form y = mx + c , where m is the slope and c is the y - intercept.

2x + 5y = 10

5y = -2x + 10

y = -2/5x + 10/5

y = -2/5x + 2

This means that the slope is -2/5 ,the line that is parallel to this line will also have a slope of -2/5.

using the formula:

$y-y_{1}$ = m ( $x-x_{1}$ ) to find the equation of the line , we have

y - 1 = -2/5(x -{-5})

y - 1 = -2/5 ( x + 5 )

5y - 5 = -2 ( x + 5 )

5y - 5 = -2x - 10

5y + 2x = -10 + 5

therefore :

2x + 5y = -5 is the equation of the line that is parallel to 2x + 5y = 10

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3 years ago

Read 2 more answers

Solve the system by substitution 10x-2y=-16 and y=3x

lesantik [10]

The answer would be x=-4.

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3 years ago

a)express x^2+12x+11 in the form (x+p)^2+q b)A curve has equation y=x^2+12x+11. What are the co-ordinates of the turning point o

sveticcg [70]

a) (x+6)^2-25

b) (-6, -25)

Step-by-step explanation:

Perfect square trinomial! If you have 12x, divide by two and get 6, so we have (x+6)^2+q. Then solve for q. You get q as -25.

For b, we just take the vertex from vertex form. We get x+6=0 so x=-6, and q = -25, so the answer is (-6, -25).

Hope that helped,

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Step-by-step explanation:

I promise

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bagirrra123 [75]

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