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maksim [4K]
3 years ago
6

The diagonal of a rectangle is 13 units. One side of the rectangle is 12”. Find the length of the shortest side of the rectangle

.
Mathematics
1 answer:
exis [7]3 years ago
7 0

Answer:

explain more

Step-by-step explanation:

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What does 9.6 divided by 0.08
Mila [183]

Answer:

120

Step-by-step explanation:

9.6÷0.08=120

hope this helped

5 0
3 years ago
-4 -12
Zarrin [17]

Answer:

Slope(m)=3

Y-intercept= 0

y = 3x +0

Proportional

Step-by-step explanation:

m = -6--12/-2--4

m=6/2

m=3

-12 = 3(-4) + b

-12 = -12 + b

0=b

3 0
3 years ago
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Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
3. The diagonal of a rectangular field is 169 m. Ifthe ratio of the length to the width is 12:5, find the: (a) (b) dimensions; p
Kazeer [188]

The dimensions of the rectangle are length 156 m and a width of 65m, and a perimeter P = 442m

<h3>How to find the dimensions of the rectangle?</h3>

For a rectangle of length L and width W, the diagonal is:

D = \sqrt{L^2 + W^2}

Here we know that the diagonal is 169m.

And the ratio of the length to the width is 12:5

This means that:

W = (5/12)*L

Replacing all that in the diagonal equation:

169 = \sqrt{((5/12)^2*L^2 + L^2} \\\\169^2 = (25/144)*L^2 + L^2 = ( 25/144 + 1)*L^2\\\\\frac{169}{\sqrt{25/144 + 1} } = L = 156

So the length is 156 meters, and the width is:

W = (5/12)*156 m = 65m

Finally, the perimeter is:

P = 2*(L + W) = 2*(156 m + 65m) = 442m

If you want to learn more about rectangles:

brainly.com/question/17297081

#SPJ1

8 0
2 years ago
Ill mark brainlist plss help
mojhsa [17]

Answer:

w=20

Step-by-step explanation:

Solve for  w  by cross multiplying.

6 0
3 years ago
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