The diagonal of a rectangle is 13 units. One side of the rectangle is 12”. Find the length of the shortest side of the rectangle
1 answer:
You might be interested in
Answer:
2.0 x
Step-by-step explanation:
1. length = 3.2 x m
width = 1.6 x m
Area of a rectangle = length x width
= (3.2 x ) x (1.6 x
)
= 5.12 x
2. length = 1.28 x m
width = 8 x m
Area of a rectangle = length x width
= (1.28 x ) x (8 x
)
= 1.024 x
=
= 20
= 2.0 x
Thus,
The area of rectangle 2 is 2.0 x times greater than the area of rectangle 1.
GiveN:
- ABCD is a parallelogram.
- AC and BD are the diagonals.
- DE = 28 units
To FinD:
- Value of x in length of BE?
Step-wise-Step Explanation:
We know that
In any parallelogram, the diagonals (lines linking opposite corners) bisect each other. Then, AE = EC for diagonal AC and BE = DE for diagonal BD.
⇒ BE = DE
⇒ x - 4 = 28 units
⇒ x = 32 units
Hence, The required value of x here is <u>3</u><u>2</u><u> </u><u>units</u><u>.</u>