565 is the correct answer
Answer:your question seems incomplete but if you looking to find the resulting equation to solve for temperature at a particular time you can use this 28t^2
Step-by-step explanation:
F'(t) = 7(0.8)t
Integrating the RHS
Temp= integral of f'(t)= 28t^2
Therefore, T(°c)= 28t^2
2,000 + 1,000 = 3,00 so you would have $2,000 more to get to 3,000
Two of the side lengths and one of the angles of both of the triangles. Hope this helps!
