The space diagonal will have length ...
... d = √(1² +4² +2²) = √(1 +16 +4) = √21
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This can be found using the Pythagorean theorem. A drawing can help. Find the length of any face diagonal, then use that length as the leg of a right triangle whose hypotenuse is the space diagonal and whose other leg is the edge length not used in the first calculation.
Answer:
x=3 or x=−9
Step-by-step explanation:
Step 1: Subtract 27 from both sides.
x2+6x−27=27−27
x2+6x−27=0
Step 2: Factor left side of equation.
(x−3)(x+9)=0
Step 3: Set factors equal to 0.
x−3=0 or x+9=0
x=3 or x=−9
Answer:
x=3 or x=−9
Answer:
The area of the regular hexagon is 
Step-by-step explanation:
we know that
The area of a regular hexagon can be divided into 6 equilateral triangles
so
step 1
Find the area of one equilateral triangle
we have
----> is the apothem
substitute
step 2
Find the area of 6 equilateral triangles
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer:
I Got You 64 is the correct answer.
Step by-step explanation:
7 x 2= 14
5 x 10= 50
50 + 14= 64
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