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tamaranim1 [39]
3 years ago
11

Ill give the brainliest

Mathematics
1 answer:
olga2289 [7]3 years ago
8 0

Answer: I think its A and C

Step-by-step explanation:

Please mark me brainliest

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Find the 15th term of the arithmetic sequence 13,8,3,-2
otez555 [7]

Answer:

B

Step-by-step explanation:

7 0
2 years ago
How many whole numbers are less than 600 but are multiples for both 8 and 11
shutvik [7]

Answer:

6

Step-by-step explanation:

11 = 11*1

8 = 2*4

They have no common factors, so the LCM (least common multiple) is

2*4*11 = 88

The multiples of 8 and 11 below 600 are multiples of 88

88*1 =88

88*2 =176

88*3 =264

88*4 =352

88*5 =440

88*6 =528

This is the last multiple because if we add 88 if would be over 600

7 0
3 years ago
The sum of twelve times p and d
KIM [24]
<h3>Hey there! </h3><h3>"The sum of twelve times p and d" </h3><h3>Firstly, you could pull out your key terms for better understanding of the expression</h3><h3>Here's your key terms </h3>
  • Sum
  • (Of) twelve
  • Times
  • P and D
<h3>Let's find out what each term mean for setting up your problem , easier </h3>

Sum = add (+)

Twelve = 12

p & d = p & d (since they are <em><u>unknown numbers</u></em>)

SO, this means that your answer SHOULD look like this: 12p + d

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)


6 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 149 millimeters,
Artemon [7]

Answer:

The probability that the sample mean would differ from the population mean by more than 0.5 millimeters is 0.2420.

Step-by-step explanation:

Let <em>X</em> = the diameter of the steel bolts manufactured by the steel bolts manufacturing company Thompson and Thompson.

The mean diameter of the bolts is:

<em>μ</em> = 149 mm.

The standard deviation of the diameter of bolts is:

<em>σ</em> = 5 mm.

A random sample, of size <em>n</em> = 49, of steel bolts are selected.

The population of the diameter of bolts is not known.

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

The mean of the sampling distribution of sample mean is:

\mu_{\bar x}=\mu=149\ mm

The standard deviation of the sampling distribution of sample mean is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5}{\sqrt{49}}=0.7143

Compute the probability that the sample mean would differ from the population mean by more than 0.5 millimeters as follows:

P(\bar X>\bar x)=P(\frac{\bar X-\mu_{\bar x}}{\sigma _{\bar x}}>\frac{0.50}{0.7143})\\=P(Z>0.70)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 0.5 millimeters is 0.2420.

8 0
3 years ago
Read 2 more answers
*HELP PLEASE*<br> *WILL GET BRAINLIEST ANSWER*
Svetach [21]

You could do any of the following:


10:2 / 9:3

10/2 / 9/3

6 0
3 years ago
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