Answer:
There are 6 coins in nickels and 9 coins in quarters.
Step-by-step explanation:
Now, to find the solution.
According to question:
The number of nickels =
.
The number of quarters = ![y.](https://tex.z-dn.net/?f=y.)
So, the total number of coins:
![x+y=15.](https://tex.z-dn.net/?f=x%2By%3D15.)
He had 3 more quarters than nickels.
Thus,
.....(1)
Now, to get the solution:
![x+y=15](https://tex.z-dn.net/?f=x%2By%3D15)
Substituting the equation (1):
![x+(x+3)=15](https://tex.z-dn.net/?f=x%2B%28x%2B3%29%3D15)
![x+x+3=15](https://tex.z-dn.net/?f=x%2Bx%2B3%3D15)
![2x+3=15](https://tex.z-dn.net/?f=2x%2B3%3D15)
<em>Subtracting both sides by 3 we get:</em>
<em />
<em />
<em>Dividing both sides by 2 we get:</em>
![x=6.](https://tex.z-dn.net/?f=x%3D6.)
<em>The number of nickels = 6.</em>
Now, substituting the value of
in equation (1):
![y=x+3\\\\y=6+3\\\\y=9.](https://tex.z-dn.net/?f=y%3Dx%2B3%5C%5C%5C%5Cy%3D6%2B3%5C%5C%5C%5Cy%3D9.)
<em>The number of quarters = 9.</em>
Thus, there are 6 coins in nickels and 9 coins in quarters.