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kobusy [5.1K]
2 years ago
12

PLEASE HELP I WILL MARK YOU BRAINLIEST How many moles of FeCl2 do you need to react 5 moles of Cl2?

Chemistry
1 answer:
lisabon 2012 [21]2 years ago
4 0

Answer:

1. Ok, so you have a 1:1 ratio of FeCl2 to FeCl3, which is shown by the fact that if you react 2 moles of FeCl2 you get 2 moles of FeCl3. So therefore, if you react 4 moles of FeCl2, you'd form 4 moles of FeCl3.

2. You have a 1:2 ratio of Cl2 to FeCl2, for every 1 mole of Cl2, you need 2 moles of FeCl2, so therefore, for 7 moles of Cl2, you need 2x7moles = 14 moles

3. 1:1 ratio. So you start with 2.28moles.

4. 1:2 ratio of Cl2 to FeCl2, so therefore to get from FeCl2 to Cl2 you need to divide by 2. Therefore, you need 3.25moles / 2 = 1.625 moles

Explanation:

pls mark branliest

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Answer:

kp= 3.1 x 10^(-2)

Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

                                2SO2      +        O2         ⇄              2SO3

Initial                      3.4 atm           1.3 atm                         0 atm

Change                    -2x                    - x                                + 2x

Equilibrium            3.4 - 2x            1.3 -x                          0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

                               2SO2             +          O2              ⇄              2SO3

Equilibrium        3.4 - 0.52                1.3 - 0.26                     0.52 atm

Equilibrium        2.88 atm                 1.04 atm                      0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

Kp=\frac{PSO3^2}{PSO2^2 PO2}=\frac{(0.52)^2}{(2.88)^2(1.04)}=0.03135

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The empirical formula for the caproic acid, given the combustion analysis data is C₃H₆O

We'll begin bey obtaining the mass of carbon, hydrogen and oxygen in the compound. This is illustrated below:

How to determine the mass of C

  • Mass of CO₂ = 9.78 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
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Mass of C = (12 / 44) × 9.78

Mass of C = 2.67 g

How to determine the mass of H

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Mass of H = (2 / 18) × 4

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How to determine the mass of O

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Mass of O = (mass of compound) – (mass of C + mass of H)

Mass of O = 4.30 – (2.67 + 0.44)

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<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as follow:

  • C = 2.67 g
  • H = 0.44 g
  • O = 1.19 g
  • Empirical formula =?

Divide by their molar mass

C = 2.67 / 12 = 0.2225

H = 0.44 / 1 = 0.44

O = 1.19 / 16 = 0.074

Divide by the smallest

C = 0.2225 / 0.074 = 3

H = 0.44 / 0.0744 = 6

O = 0.074 / 0.074 = 1

Thus, the empirical formula of the compound is C₃H₆O

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