Answer:
(A) N4H6 (B) H2O (C) LiH (D) C12H26
Explanation:
The given compounds have been arranged from left to right in order of increasing percentage by mass of hydrogen.
The percent by mass of hydrogen can be calculated by mass of hydrogen in that compound divided by total mass of that compound and finally multiplying the result with 100 to obtain the required percentage.
Noble gas. Noble gas, any of the seven chemical elements<span> that make up Group 18 (VIIIa) of the </span>periodic table<span>. The </span>elements<span> are </span>helium<span> (</span>He<span>), </span>neon<span> (</span>Ne<span>), argon (Ar), krypton (Kr), </span>xenon<span> (</span>Xe<span>), radon (Rn), and oganesson (Og)</span>
H2SO4 + Na2CO3 → Na2SO4 + CO2 + H2O
The molarity of sulfuric acid if 1.78 L were used in the above reaction is
0.453 M (answer 2)
Calculation
find the moles of water produced = mass/molar mass
= 14.5 g /18 g/mol = 0.806 moles
by use of of mole ratio between H2So4 to H2O which is 1:1 the moles of H2SO4 is also = 0.806 moles
Molarity of H2SO4 is therefore = moles/volume in liters
= 0.806 mol/ 1.78 L = 0.453 M (answer 2)
Explanation:
Let compound X be 100g.
Molar mass of carbon = 12g/mol
Moles of C in compound X = 54.54/12 = 4.54mol.
Molar mass of hydrogen = 1g/mol
Moles of H in compound X = 9.09/1 = 9.09mol.
Molar mass of oxygen = 16g/mol
Moles of O in compound X = 36.37/16 = 2.27mol
Ratio of C:H:O = 4.54:9.09:2.27 = 2:4:1.
Hence, the empirical formula of X is C2H4O.
