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Studentka2010 [4]
3 years ago
5

A sample of oxygen gas occupies a volume of 335 mL at 704 torr pressure. What volume will it occupy at 852 torr pressure?

Chemistry
1 answer:
Drupady [299]3 years ago
3 0

Answer:

276.81cm³

Explanation:

V1 = 335mL

P1 = 704 torr

V2 = ?

P2 = 852 torr.

V1 = 335cm³ (1mL = 1cm³)

From Boyle's law,

The volume of fixed mass of gas is inversely proportional to its pressure provided the temperature remains constant.

P1 * V1 = P2 * V2

V2 = (P1 * V1) / P2

V2 = (704 * 335) / 852

V2 = 235840 / 852

V2 =276.807

V2 = 276.81 cm³

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Which of the statements are true ONLY for lonic compounds? (select all that apply)
DENIUS [597]

Answer:

Smallest unit is called a formula unit

Forms between a metal and a nonmetal

Formed by the transfer of electrons

Good conductor when dissolved in water

Forms repeating patterns in a crystal lattice structure

Have high melting and boiling points

Explanation:

5 0
3 years ago
Technetium has a half-life of six hours. If you obtain 100g of a pure technetium sample, after 18 hours how much of the pure sub
IgorLugansk [536]

Answer:

After 18 hours, the amount of pure technetium that will be remaining is 12.5 grams

Explanation:

To solve the question, we note that the equation for half life is as follows;

N(t) = N_0 (\frac{1}{2} )^{\frac{t}{t_{1/2}}

Where:

N(t) = Quantity of the remaining substance  = Required quantity

N₀ = Initial radioactive substance quantity  = 100 g

t = Time duration  = 18 hours

{t_{1/2} = Half life of the radioactive substance  = 6 hours

Therefore, plugging in the values, we have;

N(t) = 100 (\frac{1}{2} )^{\frac{18}{6}} = 100 (\frac{1}{2} )^{3} =  \frac{100 }{8} = 12.5 \ grams

Therefore, after 18 hours, the amount of pure technetium that will be remaining = 12.5 grams.

6 0
3 years ago
A- Gases do not have mass.
finlep [7]
The answer is going to be d. hope that helped
7 0
3 years ago
SOLVE FAST....⚡⚡⚡
Rina8888 [55]

Answer:

thanks for the points

Explanation:

have a nice day

6 0
2 years ago
A piece of PVC plumbing pipe displaces 60 mL when placed into a container of water. If the pipe has a mass of 78g, what is the d
babymother [125]
Use the equation d=m/v

your mass or "m" is 78 g

your volume or "v" is 60mL

if you plug those values into the equation it will look like this:

d=78/60
d=1.3g/mL should be what you come up with
3 0
3 years ago
Read 2 more answers
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