Distance = rate*time
distance/time = rate
The race course is 3 miles around and Jeff does it twice, so the distance he goes = 2*3 miles = 6 miles.
He takes 20 minutes to go around once and 25 minutes to go around the second time, so the total time = 20 min + 25 min = 45 min.
His speed is miles per hour, not miles per minute, so convert 45 minutes to a hours:
45 min/60 min = 0.75 hours <span>distance/time = rate = 6 miles/0.75 hours = 8 mph</span>
By the pythagorean theorem, we know that (leg1)^2 + (leg2)^2 = hypotenuse^2. to see the proof refer to the following link: http://jwilson.coe.uga.edu/EMT668/EMT668.Student.Folders/HeadAngela/essay1/Pythagorean.html
plugging in what we know we have 16^2 + leg^2 = 20^2 and we find that leg = 12.
Answer:
x = 13
Step-by-step explanation:
3x + 2x + 5 = 60
5x + 5 = 60
5x = 65
x = 13
Answer:
BC = 23
Step-by-step explanation:
Since ∠ A = ∠ C then the triangle is isosceles with AB = BC, that is
3x + 14 = x + 20 ( subtract x from both sides )
2x + 14 = 20 ( subtract 14 from both sides )
2x = 6 ( divide both sides by 2 )
x = 3
Thus
BC = 3x + 14 = 3(3) + 14 = 9 + 14 = 23
