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2 years ago

(3x^2) (2x^5)use the properties of exponents to simplify

Mathematics

1 answer:

Solnce55 [7]2 years ago

4 0

Answer:

6x^7.

Step-by-step explanation:

The exponent property for this would be that

x^a * x^b = x^a + b.

So x^2 * x^5 = x^2 + 5 or x^7.

The other part is just multiplying the coefficients 3 and 2, which is 6.

Put these together and you get your answer 6x^7.

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Benson sells vacuum cleaners on a commission he earns $75 for each vacuum cleaners sucks how many vacuum cleaner should he sell

Digiron [165]

Answer: Read below!

Step-by-step explanation:

You would want to start off by dividing 75 by 1,400. That will get you your answer.

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3 years ago

Peter placed an order with an online nursery for 6 apple trees and 5 azaleas and the order came to $147. The next order for 3 ap

Setler79 [48]

Answer:

$243

Step-by-step explanation:

The first order you made :

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And total cast was:

$147

The secant order you order was:

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And total cast was:

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5 0

2 years ago

Read 2 more answers

Show me how to get this answer show your work

Rama09 [41]

We know that angle MKJ is comprised of angle MKL and angle LKJ. That means if we add MKL and LKJ, we should get 80 degrees, which is the measure of angle MKJ.

$MKL + LKJ= MKJ \implies \\ 2x+10+3x-5=80 \implies \\ 5x+5=80 \implies\\ 5x=75 \implies \\ x=15$

So, we know that our x is 15. That is not enough to tell whether KL is an angle bisector, because we have to evaluate both MKL and LKJ with x=15, so:

$MKL=2(15)+10 = 40\\ LKJ=3*15-5=40$

So we see that these two angles are actually bisectors, and the third question best describes this phenomenon.

6 0

3 years ago

Read 2 more answers

The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and

Scorpion4ik [409]

Answer:

$\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)$

Step-by-step explanation:

The PDF of X is

$\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)$

The PDF of Y is

$\bf g(x)=\mu e^{-\mu x}\;(x\geq0)$

The means of X and Y are respectively,

$\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}$

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

$\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)$

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2 years ago

A. 2x = 5<br><br> What would be the answer I don’t know anyone help me before the 28th

Aleksandr [31]

Answer:

2.5

Step-by-step explanation:

4 0

2 years ago

(3x^2) (2x^5)use the properties of exponents to simplify​

(3x^2) (2x^5)use the properties of exponents to simplify