Answer:
to collect measurable, empirical evidence in an experiment related to a hypothesis the results aiming to support or contradict a theory.
Explanation:
Answer:
0.019 g.
Explanation:
- Firstly, we need to find the no. of moles of oxygen gas:
- We can use the general law of ideal gas: <em>PV = nRT.
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where, P is the pressure of the gas in atm (P = 1.02 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 28°C + 273 = 301.0 K).
∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.
- To find the mass of oxygen gas, we have:
<em>no. of moles = mass/molar mass.</em>
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∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.
Percent by volume is equal to the volume of the solute over the total volume of the solution times 100%. Therefore,
30 = volume of ethanol / 100 mL x 100
volume of ethanol = 30 mL
Hope this answers the question. Have a nice day.
Answer:
A. 0.0005u
Explanation:
The mass of an electron in amu = 9.1*10-311.66*10-27=0.0005u.
