Answer:
The final molarity of the diluted oxalic acid solution is 0.002504 M
Explanation:
Step 1: Data given
Mass of oxalic acid (H2C2O4) = 0.5636 grams
Volume of the solution = 100.0 mL = 0.100 L
A 10 ml of this solution diluted in 250 ml of solution.
Molecular weight of H2C2O4 = 90.03 g/mol
Step 2: Calculate initial moles of H2C2O4
Moles H2C2O4 = mass / molar mass
Moles H2C2O4 = 0.5636 grams / 90.03 g/mol
Moles H2C2O4 = 0.00626 moles
Step 3: Calculate molarity of the solution
Molarity = moles / volume
Molarity = 0.00626 moles / 0.100 L
Molarity = 0.0626 M
Step 4: Calculate moles of a 10.00 mL aliquot
Moles = 0.0626 M * 0.010 L
Moles = 0.000626 moles
Step 5: Calculate the new molarity
Molarity = 0.000626 moles / 0.250 L
Molarity = 0.002504 M
The final molarity of the diluted oxalic acid solution is 0.002504 M
