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Anettt [7]
3 years ago
6

The mass of an electron is close to: A. 0.00055u. B. 0.05u. C. 10-10 u. D. 0.0001u

Chemistry
2 answers:
ratelena [41]3 years ago
8 0

Answer:

ignition itxoyxuxgxitxog ignition otd9xots84dizts8ot itsot itzot ist lgotxpg 9xoy x95clh

Explanation:

cuz

Debora [2.8K]3 years ago
7 0

Answer:

A. 0.0005u

Explanation:

The mass of an electron in amu = 9.1*10-311.66*10-27=0.0005u.

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A 47.1 g sample of a metal is heated to 99.0°C and then placed in a calorimeter containing 120.0 g of water (c = 4.18 J/g°C) at
wlad13 [49]

Answer : The metal used was iron (the specific heat capacity is 0.44J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

C_1 = specific heat of metal = ?

C_1 = specific heat of water = 4.18J/g^oC

m_1 = mass of metal = 47.1 g

m_2 = mass of water = 120 g

T_f = final temperature of water = 24.5^oC

T_1 = initial temperature of metal = 99^oC

T_2 = initial temperature of water = 21.4^oC

Now put all the given values in the above formula, we get

47.1g\times c_1\times (24.5-99)^oC=-120g\times 4.18J/g^oC\times (24.5-21.4)^oC

c_1=0.44J/g^oC

Form the value of specific heat of metal, we conclude that the metal used in this was iron.

Therefore, the metal used was iron (the specific heat capacity is 0.44J/g^oC).

3 0
3 years ago
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