PLEASE HELP Aria made 9 pounds of fudge.She separates the fudge into 3/4 pound portions. She sells each portions for $6.50.if sh
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Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Answer: Option A
The median is the same as the _ Second quartile_.
Step-by-step explanation:
Given a series of data ordered from least to greatest, the median is the value that is in the center.
That is, the median represents the value that divides 50% of the data.
In the same way, the first quartile is the value that divides 25% of the data and the third quartile
is the value that divides 75% of the data.
The second quartile is the number that divides 50% of the data.
Then notice that the second quartile is equal to the median
Then te answer is the option A.