Write the standard equation for the hyperbola with the following conditions: vertices: (-2, -3) and (6, -3) foci: (-4, -3) and (
8, -3)
1 answer:
Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
You might be interested in
<u>Answer-</u>
<em>The height of the prism is</em><em> 6 units</em>
<u>Solution-</u>
As the base of the prism is a hexagon consisting of 2 congruent isosceles trapezoids.
So,
And,
Also,
Putting all the values,
As the volume is given, so
we know, that the angle formed by an arc at the center of the circle is two times the angle formed by same arc on any point on the circumference,
So,
=》
hence, correct answer is B.
ANSWER
EXPLANATION
The given fraction is,
To get an equivalent fraction, we multiply both the numerator and the denominator by the same quantity that will give us
w²+w-20
in the denominator.
This implies that,
We multiply out the numerators and denominators using the distributive property to obtain,
This simplifies to
EXPLANATION
The given fraction is,
To get an equivalent fraction, we multiply both the numerator and the denominator by the same quantity that will give us
w²+w-20
in the denominator.
This implies that,
We multiply out the numerators and denominators using the distributive property to obtain,
This simplifies to