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Anuta_ua [19.1K]
3 years ago
7

Help with figuring this out please

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:

15, 12 12331 12231215542478246325

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What is the value of x
ICE Princess25 [194]

Answer:

124°

Step-by-step explanation:

Step 1:

72° + 52° = x       Remote Interior ∠'s

Step 2:

124° = x       Add

Answer:

x = 124°

Hope This Helps :)

7 0
4 years ago
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Brendan has a cherry tree in his yard. Currently the tree is 9 feet tall. That is 50% taller than it was when Brendan planted it
adell [148]

Answer:

Step-by-step explanation:

The tree when he got it was half the size it is now.  If the tree is 9 feet tall, back then it was half of 9 feet, which is 4.5 feet.

5 0
3 years ago
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Helppp please I need help with this ASAP
galben [10]

Answer:

-7 < -5

Step-by-step explanation:

-5 is greater than -7

6 0
3 years ago
Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +
Veronika [31]

Answer:

Verified

y(x) = \frac{3Ln(x) + 3}{x}

y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

- A general solution to the above ODE is also given as:

                          y = \frac{3Ln(x) + C  }{x}

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

- Therefore, the complete solution to the given ODE can be expressed as:

                        y ( x ) = \frac{3Ln(x) + 3 }{x}

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)

- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

Download docx
6 0
3 years ago
Joann has a jug containing 128 ounces of milk. She drinks 14 ounces of milk each day. Enter the function f(x) that represents th
Tatiana [17]

Answer:

f(x)=128-14x

Step-by-step explanation:

So, we started out with 128 ounces of milk.

Each day, Joann drinks 14 ounces of milk.

Therefore, the amount of milk left over after x days is 14 times x subtracted from 128.

Therefore, our function is:

f(x)=128-14x

And we're done!

6 0
3 years ago
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