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3 years ago

21.evaluate 22.find dy/dx

Mathematics

2 answers:

Sauron [17]3 years ago

4 0

<h2>Long short story: I tried ;-; </h2>

Viefleur [7K]3 years ago

3 0

9514 1404 393

Answer:

y' = -y/x

Step-by-step explanation:

It looks like you have ...

e^z -z = 0 . . . . . where z = xy

Differentiating with respect to x gives ...

z'·e^z -z' = 0

z'(e^z -1) = 0

The zero-product rule tells you this is true for e^z = 1, which is not useful for finding y', and for z' = 0, which is.

z = xy

z' = y +xy' = 0

y' = -y/x

_____

<em>Additional comment</em>

There appear to be no real values of x and y that will make your equation true.

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3 years ago

21.evaluate 22.find dy/dx​

21.evaluate 22.find dy/dx