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Anettt [7]
3 years ago
7

21.evaluate 22.find dy/dx​

Mathematics
2 answers:
Sauron [17]3 years ago
4 0
<h2>Long short story: I tried ;-; </h2>

Viefleur [7K]3 years ago
3 0

9514 1404 393

Answer:

  y' = -y/x

Step-by-step explanation:

It looks like you have ...

  e^z -z = 0 . . . . . where z = xy

Differentiating with respect to x gives ...

  z'·e^z -z' = 0

  z'(e^z -1) = 0

The zero-product rule tells you this is true for e^z = 1, which is not useful for finding y', and for z' = 0, which is.

  z = xy

  z' = y +xy' = 0

  y' = -y/x

_____

<em>Additional comment</em>

There appear to be no real values of x and y that will make your equation true.

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Answer:

a.\hspace{3} \frac{6}{38} = 0.15789474\\\\b.\hspace{3} \frac{45}{55} = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 0.14285714\\\\d.\hspace{3} \frac{35}{28} = 1.25\\\\e.\hspace{3} \frac{1030}{2030} = 0.50738916

Step-by-step explanation:

Rational numbers, expressed as decimal numbers, are obtained from the operation of division between the integer of the numerator and the integer of the denominator. Then:

a.\hspace{3} \frac{6}{38} = 6\div38 = 0.15789474\\\\ b.\hspace{3} \frac{45}{55} = 45\div55 = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 4\div28 = 0.14285714\\\\ d.\hspace{3} \frac{35}{28} = 35\div28 = 1.25\\\\ e.\hspace{3} \frac{1030}{2030} = 1030\div2030 = 0.50738916

3 0
3 years ago
Solve the inequality.<br><br> 2(4 + 2x) ≥ 5x + 5?<br><br> x ≤ ?
NikAS [45]
2(4+2x)≥5x+5
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Hope this helps
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<u>Answer:</u>

\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}

<u>Step-by-step explanation:</u>

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}

\bf \implies n_{cubes} = \dfrac{20cm \times  6cm \times 4cm .}{2cm  \times 2cm  \times 2cm } \\\\\bf\implies n_{cubes}  = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }

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