Question

21.evaluate 22.find dy/dx​

Answer 1

Long short story: I tried ;-;

Answer 2

9514 1404 393

Answer:

  y' = -y/x

Step-by-step explanation:

It looks like you have ...

  e^z -z = 0 . . . . . where z = xy

Differentiating with respect to x gives ...

  z'·e^z -z' = 0

  z'(e^z -1) = 0

The zero-product rule tells you this is true for e^z = 1, which is not useful for finding y', and for z' = 0, which is.

  z = xy

  z' = y +xy' = 0

  y' = -y/x

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Additional comment

There appear to be no real values of x and y that will make your equation true.