There are 3 in. of snow on the ground when it begins to snow 0.5 in./h.
Initial depth of snow = 3 in.
it begins to snow 0.5 in./h. The constant rate of snow is 0.5. So slope = 0.5
Let x be the number of hours
y be the total depth of the snow
To frame linear equation we use y=mx+b
where m is the slope and b is the y intercept (initial depth of snow)
We know m=0.5 and b=3
Replace it in the equation
y = 0.5x + 3
The linear equation that represents the total depth of the snow(y), in inches, after x hours
is y= 0.5x + 3
Answer:
1 and 4/35
Step-by-step explanation:
Use distribution property to solve:
6/5 × -5/7 -3/4 -5/7 × 4/5 = -5/7 ( 6/5 - 3/4 ) x 4/5 = -5/7 ( 24/20 - 15/20 ) x 4/5 = -5/7 (-39/20) x 4/5 = 780 / 700 = 1 4/35
Answer:
6x^2+5x-6
Step-by-step explanation:
Square=a^2
trapezoid: a+b over 2 times height
triangle=bxh divide by 2
parallelogram= bxh
